SOLUTION: Could you please show me how to set up and answer this question: Jose takes the same amount of time to walk 3 miles as it takes Carlos to ride his bike 5 miles. If Carlos trave

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Question 92408: Could you please show me how to set up and answer this question:
Jose takes the same amount of time to walk 3 miles as it takes Carlos to ride his bike 5 miles. If Carlos travels 5 miles per hour faster than Jose, what is Carlos' speed?
Thank you
Found 2 solutions by mathispowerful, checkley71:
Answer by mathispowerful(115) About Me  (Show Source):
You can put this solution on YOUR website!
Could you please show me how to set up and answer this question:
Jose takes the same amount of time to walk 3 miles as it takes Carlos to ride his bike 5 miles. If Carlos travels 5 miles per hour faster than Jose, what is Carlos' speed?
The key to set up the equation is to find the quantities that equal each other.
in this case: they use the same time.
How to represent time?
time = distance divided by speed.
so we need to do division and let them equal.

Here is the solution
Let Jose's speed be x
Carlos' speed x + 5
then 3%2Fx+=+5%2F%28x%2B5%29
this is a proportion, so we do cross multiplication
3(x+5) = 5x
expand it: 3x + 15 = 5x
solve it, we get x =7.5
but x is Jose's speed, for Carlos
x+5 = 7.5+5 = 12.5 mph

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
DISTANCE=RATE*TIME.
SEEING AS THE TIMES ARE EQUAL THEN THE D/R ARE EQUAL.
3/R=5/(R+5) NOW CROSS MULTIPLY
5R=3(R+5)
5R=3R+15
5R-3R=15
2R=15
R=15/2
R=7.5 MPH. FOR JOSE
7.5+5=12.5 MPH. FOR CARLOS
3/7.5=5/12.5 CROSS MULTIPLY
5*7.5=3*12.5
37.5=37.5