SOLUTION: A real estate agent has 8 master keys to open
several new homes. Only 1 master key will open any
given house. If 40% of these homes are usually left
unlocked, what is the probab
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-> SOLUTION: A real estate agent has 8 master keys to open
several new homes. Only 1 master key will open any
given house. If 40% of these homes are usually left
unlocked, what is the probab
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Question 924032: A real estate agent has 8 master keys to open
several new homes. Only 1 master key will open any
given house. If 40% of these homes are usually left
unlocked, what is the probability that the real estate
agent can get into a specific home if the agent selects
3 master keys at random before leaving the office? Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! p(correct key) = 1/8 = .125
p(unlocked) = .40
p(locked) = .60
.........
If Locked
n = 3 keys
p(x = 1correct) = binompdf(3, .125, 1) = .2871
.......
P(Can enter) = P(Unlocked & enter) + P(Locked & enter)
P(Can enter) = .40(1) + .60(.2871) = .5723 0r 57.23% of the time
