SOLUTION: given [a a^2 1+a^3; b b^2 1+b^3; c c^2 1+c^3]=0 where a,b and c are all different. Prove that 1+abc=0

Algebra ->  Matrices-and-determiminant -> SOLUTION: given [a a^2 1+a^3; b b^2 1+b^3; c c^2 1+c^3]=0 where a,b and c are all different. Prove that 1+abc=0      Log On


   

Question 924003: given
[a a^2 1+a^3; b b^2 1+b^3; c c^2 1+c^3]=0
where a,b and c are all different. Prove that 1+abc=0
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
A matrix is never equal to a number - they are different types of mathematical objects. What needs to be done is not clear to me from the given information please re-post with a clear and complete question :)