SOLUTION: A rectangle is 3 times as long as it is wide. If the length is increased by 6 and the width by 8, the area is increased by 108. Find the perimeter of the original rectangle. Thanks

Algebra ->  Equations -> SOLUTION: A rectangle is 3 times as long as it is wide. If the length is increased by 6 and the width by 8, the area is increased by 108. Find the perimeter of the original rectangle. Thanks      Log On


   

Question 923890: A rectangle is 3 times as long as it is wide. If the length is increased by 6 and the width by 8, the area is increased by 108. Find the perimeter of the original rectangle. Thanks for your help.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

     .

A = Lw

.....Original width =  w and L = 3w

(3w+6)(w+8) - (3w)w= 108

3w^2 + 30w + 48 - 3w^2 = 108

30w = 60

w = 2   and L = 6 3%2A2

......

P = 2L + 2w

P(original) = 2*2 + 2*6 = 16units