SOLUTION: simplify (3x^2+7x-40)+(x+5) a. 3x+2 b. 3x+8 c. 3x-2 d. 3x-8 my test is tomorrow and i still dont understand how to work this kind of problem. i've tried to divide but it has

Algebra ->  Rational-functions -> SOLUTION: simplify (3x^2+7x-40)+(x+5) a. 3x+2 b. 3x+8 c. 3x-2 d. 3x-8 my test is tomorrow and i still dont understand how to work this kind of problem. i've tried to divide but it has      Log On


   

Question 92388: simplify (3x^2+7x-40)+(x+5)
a. 3x+2
b. 3x+8
c. 3x-2
d. 3x-8
my test is tomorrow and i still dont understand how to work this kind of problem. i've tried to divide but it hasnt given me one of the choices i have for answers. please help?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
if the two expressions are divided (rather than added as indicated); then factoring can help

(3x^2+7x-40)/(x+5) ... ((3x-8)(x+5))/(x+5)=(3x-8)

what type of division did you try? long division can be done with these expressions