Question 923872: A coin bank has 250 coins,dimes, quarters, worth $42.25. How many of each type of coin are there? Found 2 solutions by TimothyLamb, Cromlix:Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = dimes
y = quarters
---
x + y = 250
10x + 25y = 4225
---
put the system of linear equations into standard form
---
x + y = 250
10x + 25y = 4225
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
solution:
x = dimes = 135
y = quarters = 115
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
You can put this solution on YOUR website! A coin bank has 250 coins,dimes, quarters, worth $42.25
x + y = 250..................(1)
10x + 25y = 4225..............(2)
Multiply (1) by 25
25x + 25y = 6250.............(1)
10x + 25y = 4225.............(2)
Subtract (2) from (1)
15x = 2025
x = 135
Substitute x = 135 into (1)
x + y = 250
135 + y = 250
y = 250 - 135
y = 115
135 dimes and 115 quarters.
Hope this helps.
:-)
