SOLUTION: Suppose sin x = 1/7
cos x > 0, sin y = −2/5
and cos y < 0. Then
cos x =
cos y =
Find each of the following quantities:
sin(x + y) =
cos(x + y) =
tan(x + y) =
Algebra ->
Trigonometry-basics
-> SOLUTION: Suppose sin x = 1/7
cos x > 0, sin y = −2/5
and cos y < 0. Then
cos x =
cos y =
Find each of the following quantities:
sin(x + y) =
cos(x + y) =
tan(x + y) =
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Question 923632: Suppose sin x = 1/7
cos x > 0, sin y = −2/5
and cos y < 0. Then
cos x =
cos y =
Find each of the following quantities:
sin(x + y) =
cos(x + y) =
tan(x + y) = Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! sin x = 1/7, cos x > 0, cos x = 4√3 /7
.......
sin y = −2/5, and cos y < 0, cosy = √21 / 5
........Plug and Play
sin(x + y) = sin x cos y + sin y cos x
sin(x + y) = (1/7)(√21 /5) + (-2/5)(4√3 /7)
