SOLUTION: y=2(x+4)'2-5
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Question 923613
:
y=2(x+4)'2-5
Answer by
ewatrrr(24785)
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the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex and x = h is the Line of Symmetry
y=2(x+4)^2-5 V(-4, -5), Opens Up a = 2 > 0, x = -4 is the Line of Symmetry