SOLUTION: r=1/32v^2sin2x , where v is the initial velocity and x is the angle of evlevation. r= 10,000 ft and v= 3500 ft/sec. Find the angle x. Please help

Algebra ->  Trigonometry-basics -> SOLUTION: r=1/32v^2sin2x , where v is the initial velocity and x is the angle of evlevation. r= 10,000 ft and v= 3500 ft/sec. Find the angle x. Please help      Log On


   

Question 923535: r=1/32v^2sin2x , where v is the initial velocity and x is the angle of evlevation. r= 10,000 ft and v= 3500 ft/sec. Find the angle x. Please help
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
r=1/32v^2sin2x , where v is the initial velocity and x is the angle of elevation. r= 10,000 ft and v= 3500 ft/sec. Find the angle x.
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10,000 = (1/32)*3500^2*sin(2x)
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320,000 = 12250000*sin(2x)
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sin(2x) = 0.03
2x = arcsin(0.03) = 1.72 degrees
x = 0.86 degrees
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Cheers,
Stan H.
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