SOLUTION: Factor each of the following polynomials completly 14x^2 - 20x + 6

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Question 92350: Factor each of the following polynomials completly
14x^2 - 20x + 6
Answer by prabhjyot(165) About Me  (Show Source):
You can put this solution on YOUR website!
+14x%5E2+-+20x+%2B+6+
Compare above equation with standard quad equation ax%5E2%2Bbx%2Bc
we get
a = 14
b = -20
c = 6

Discriminant: b2-4ac = 20%5E+2-4%2A14%2A6+=+64+
Discriminant (64) is greater than zero. The equation has two solutions.
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
or
x+=+%28-%28-20%29+%2B-+sqrt%28+%28-20%29%5E2-4%2A14%2A6+%29%29%2F%282%2A14%29+
or
x1,2 = (20 ± 8) / 2*14
or
x1 = 28 / 28 = 1
x2 = 12 / 28 = 3/7
or
x1,2 = 1, 0.428
Equation factored:
14(x-1)(x-0.428)