Question 923329: The manufacturer of a new line of ink-jet printers would like to include as part of its advertising the number of pages a user can expect from a print cartridge. A sample of 10 cartridges revealed the following number of pages printed.
3,250
2,450
2,550
2,500
2,400
2,610
2,990
3,320
3,170
2,730
(a)
What is the point estimate of the population mean? (Round your answer to the nearest whole number.)
Estimated population mean
(b)
Develop a 95 percent confidence interval for the population mean. (Round your answers to 2 decimal places.)
Confidence interval for the population mean is between .... and .....
thank you so much!
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! mean = 3797, sd = 353.051775
sample of 10 cartridges (small ample size)
95 percent confidence interval for the population mean
critical t-value = 2.26
ME = 2.26(353/sqrt(10)) = 252.28
CI: 3797 - ME < u < 3797 + ME
CI: 3797 - 252.28 < u < 3797 + 252.28
CI: (3545, 4049)
........Small sample critical values:
DF Probability, p 2-tailed
0.1 0.05 0.01 0.001
1 6.31 12.71 63.66 636.62
2 2.92 4.3 9.93 31.6
3 2.35 3.18 5.84 12.92
4 2.13 2.78 4.6 8.61
5 2.02 2.57 4.03 6.87
6 1.94 2.45 3.71 5.96
7 1.89 2.37 3.5 5.41
8 1.86 2.31 3.36 5.04
9 1.83  3.25 4.78
10 1.81 2.23 3.17 4.59
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