Question 92324: Could you please help me with the set up and answer of the following problem?
1/x +6/y divided by 1/x2 - 36/y2
Thank you very much Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! [1/x +6/y]/[1/x2 - 36/y2]
= [(y+6y)/xy] / [(y^2-36x^2)/x^2y^2]
Invert the denominator and multiply:
= [(y+6y)/xy] [x^2y^2/(y-6x)(y+6x)]
= [xy/(y-6x)]
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Cheers,
Stan H.
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