SOLUTION: Could you please help me with this problem? One number is twice another number. The sum of their reciprocals is 1/4. Find the two numbers. This is what I have so far: 1/x

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Question 92322: Could you please help me with this problem?
One number is twice another number. The sum of their reciprocals is 1/4. Find the two numbers.
This is what I have so far: 1/x + 1/2x = 1/4, and then I multiplied both sides by 4x since that is the lcd and then I get a bit confused that it's not coming out right.
Thank you!

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
It should come out right the way you are doing it:
:
One number is twice another number.
One number = x; another number = 2x
:
The sum of their reciprocals is 1/4.
1%2Fx + 2%2F%282x%29 = 1%2F4
:
Find the two numbers.
Multiply the above equation by 4x and you have:
4 + 2(2) = x
:
4 + 4 = x
:
x = 8 is one number, another number = 16
:
Check:
1%2F8 + 2%2F16 = 1%2F4
2%2F16 + 2%2F16 = 4%2F16