Question 923197: Three solutions contain a certain acid. The first contains 10% acid, the second 30%, and the third 50%. A chemist wishes to use all three solutions to obtain a 50 – liter mixture containing 32% acid. If the chemist wants to use twice as much of the 50% solution as the 30% solution, how many liters of each solution should be used?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Three solutions contain a certain acid. The first contains 10% acid, the second 30%, and the third 50%. A chemist wishes to use all three solutions to obtain a 50 – liter mixture containing 32% acid. If the chemist wants to use twice as much of the 50% solution as the 30% solution, how many liters of each solution should be used?
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0.10a + 0.30b + 0.50c - 0.32*50
c = 2b
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10a + 30b + 50(2b) = 32*50
10a + 130b = 32*50
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You need one more equation statement relating 2 of the variables.
Cheers,
Stan H.
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