SOLUTION: I am confused by this question The area of a rectangle of length x is given by {{{3x^2+5x}}} Find the width of the rectangle. I would like to see how you solve the problem so tha

Algebra ->  Surface-area -> SOLUTION: I am confused by this question The area of a rectangle of length x is given by {{{3x^2+5x}}} Find the width of the rectangle. I would like to see how you solve the problem so tha      Log On


   

Question 92311: I am confused by this question The area of a rectangle of length x is given by 3x%5E2%2B5x Find the width of the rectangle.
I would like to see how you solve the problem so that I may understand for future reference.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Remember
A=L%2AW

3x%5E2%2B5x=%28x%29%2AW plug in the given information

%283x%5E2%2B5x%29%2Fx=W Divide both sides by x

3x%5E2%2Fx%2B5x%2Fx=W Split up the fraction

3x%2B5=W Divide each term by x

So the width is

W=3x%2B5


Check:

A=x%283x%2B5%29 Plug in L=x and W=3x+5

A=3x%5E2%2B5x Distribute. So this verifies our answer