SOLUTION: A baseball diamond is in the shape of a square, 90 feet on the side. What is the direct distance from home to second base

Algebra ->  Pythagorean-theorem -> SOLUTION: A baseball diamond is in the shape of a square, 90 feet on the side. What is the direct distance from home to second base       Log On


   



Question 923028: A baseball diamond is in the shape of a square, 90 feet on the side. What is the direct distance from home to second base

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
a^2 + b^2 = c^2 ... pythagorean theorem

90^2 + 90^2 = c^2

2*90^2 = c^2

c^2 = 2*90^2

c = sqrt(2*90^2)

c = sqrt(2)*sqrt(90^2)

c = sqrt(2)*90

c = 90*sqrt(2)


The exact distance is 90*sqrt(2)


90*sqrt(2) approximates to 127.27922



------------------------------------------------------------------------

Let me know if that helps or not. Thanks.

If you need more help, feel free to email me at jim_thompson5910@hotmail.com

My Website: http://www.freewebs.com/jimthompson5910/home.html