SOLUTION: I hope I have this in the right section, (1 + 2/(x + 5))/(1 + 9/(x - 2)) It is asking me to multiply the numerator and denominator of the complex fraction by the LCM.I am ge

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I hope I have this in the right section, (1 + 2/(x + 5))/(1 + 9/(x - 2)) It is asking me to multiply the numerator and denominator of the complex fraction by the LCM.I am ge      Log On


   

Question 923010: I hope I have this in the right section,
(1 + 2/(x + 5))/(1 + 9/(x - 2))
It is asking me to multiply the numerator and denominator of the complex fraction by the LCM.I am getting all of the similar ones right except for this one. THe lowest common multiple I am coming up with is (x-2) (x+5)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Do exactly as you thought! You will be able to use that product to turn the rational, complicated, expression into an expression with only a single numerator and single denominator.

.....
result should be highlight%28%28x%5E2%2B5x-14%29%2F%28x%5E2%2B12x%2B35%29%29.



...
Maybe simplifiable to

%28%28x-2%29%28x%2B7%29%29%2F%28%28x%2B5%29%28x%2B7%29%29

%28%28x-2%29cross%28%28x%2B7%29%29%29%2F%28%28x%2B5%29cross%28%28x%2B7%29%29%29

highlight%28%28x-2%29%2F%28x%2B5%29%29

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

I hope I have this in the right section,
(1 + 2/(x + 5))/(1 + 9/(x - 2))
It is asking me to multiply the numerator and denominator of the complex fraction by the LCM.I am getting all of the similar ones right except for this one. THe lowest common multiple I am coming up with is (x-2) (x+5)


%281+%2B+2%2F%28x+%2B+5%29%29%2F%281+%2B+9%2F%28x+-+2%29%29

%281+%2B+2%2F%28x+%2B+5%29%29÷%281+%2B+9%2F%28x+-+2%29%29

%28%28x+%2B+5+%2B+2%29%2F%28x+%2B+5%29%29÷%28%28x+-+2+%2B+9%29%2F%28x+-+2%29%29

%28%28x+%2B+7%29%2F%28x+%2B+5%29%29÷%28%28x+%2B+7%29%2F%28x+-+2%29%29

%28%28x+%2B+7%29%2F%28x+%2B+5%29%29*%28%28x+-+2%29%2F%28x+%2B+7%29%29 -------- Changing DIVISION to MULTIPLICATION, and INVERTING the DIVISOR

%28%28cross%28x+%2B+7%29%29%2F%28x+%2B+5%29%29*%28%28x+-+2%29%2Fcross%28%28x+%2B+7%29%29%29

highlight_green%28highlight_green%28%28x+-+2%29%2F%28x+%2B+5%29%29%29

You can do the check!! 

===================

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