SOLUTION: P(x) = -560x^2 + 5488x - 2695
where P(x) is the weekly profit in dollars when the price of a cup of
espresso is x dollars.
a) What is the weekly profit when the price per cup is
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-> SOLUTION: P(x) = -560x^2 + 5488x - 2695
where P(x) is the weekly profit in dollars when the price of a cup of
espresso is x dollars.
a) What is the weekly profit when the price per cup is
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Question 922713: P(x) = -560x^2 + 5488x - 2695
where P(x) is the weekly profit in dollars when the price of a cup of
espresso is x dollars.
a) What is the weekly profit when the price per cup is $2.75?
b) What is the total weekly overhead expense which must be covered before
any profit is made?
Using an algebraic method, determine exact answers for parts c & d. You
should use the graph of the function to check your answers.
c) What is the price of a cup of espresso which will maximize weekly
profits?
d) What is the expected maximum weekly profit? Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! P(x) = -560x^2 + 5488x - 2695
a) What is the weekly profit when the price per cup is $2.75?
P(2.75) = -560x^2 + 5488x - 2695 = $8162
b) What is the total weekly overhead expense which must be covered before
any profit is made? $2695
Using an algebraic method, determine exact answers for parts c & d. You
should use the graph of the function to check your answers.
c) What is the price of a cup of espresso which will maximize weekly
profits? $4.90 = 4.9
P(x) = -560(x -4.90)^2 x^2 + 10750.60
d) What is the expected maximum weekly profit?
$10,750.60
