SOLUTION: 1. If Jill has 18.80. She has only nickles quarters and dimes. If there are half as many quarters as there are dimes, how many nickles, quarters and dimes are there?
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Question 922660: 1. If Jill has 18.80. She has only nickles quarters and dimes. If there are half as many quarters as there are dimes, how many nickles, quarters and dimes are there?
You can put this solution on YOUR website! Since we don't know how many coins she has, there are a lot of possibilities.
18.80 = x(.25) + 2x(.10) + NICKELS.... the nickels are the problem because there can be as many as you need.
18.80 = 1(.25) + 2(.10) + 367(.05)
or
18.80 = 41(.25) + 82(.10) +7(.05)
or any number of quarters between 1 and 41. You could actually use 0 as well, and have all nickels.
Please repost if there is more to the problem.
