SOLUTION: mary bought some cans of vegetables at 89 cents per can, and some cans of soup at 99 cents per can. If she bought twice as many cans of vegetables as cans of soup, and paid at leas

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: mary bought some cans of vegetables at 89 cents per can, and some cans of soup at 99 cents per can. If she bought twice as many cans of vegetables as cans of soup, and paid at leas      Log On

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Question 922531: mary bought some cans of vegetables at 89 cents per can, and some cans of soup at 99 cents per can. If she bought twice as many cans of vegetables as cans of soup, and paid at least $10, what is the least number of vegetables she could have bought?



Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +v+ = number of cans of vegetables she bought
Let +s+ = number of cans of soup she bought
---------------
+89v+%2B+99s+%3E=+1000+ ( in cents )
+v+=+2s+
--------------
By substitution:
+89%2A2s+%2B+99s+%3E=+1000+
+178s+%2B+99s+%3E=+1000+
+277s+%3E=+1000+
+s+%3E=+3.61+
and, since
+v+=+2s+
+s+=+v%2F2+
+v%2F2+%3E=+3.61+
+v+%3E+7.22+
Since you can't have part of a can,
the least can of vegetables is 8