SOLUTION: FIND THE DISTANCE BETWEEN T(2,6) AND 3X+4Y-5=0

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Question 922397: FIND THE DISTANCE BETWEEN T(2,6) AND 3X+4Y-5=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
3X+4Y-5=0 0r y+=+%28-3%2F4%29x+%2B+5
Line Perpendicular thru P(2,6) is y+=+%284%2F3%29x+%2B+10%2F3
Lines Intersect at P(-1,2)
(2,6)
(-1,2) D = +sqrt+%28+%28x%5B1%5D-x%5B2%5D%29%5E2%2B+%28y%5B1%5D-y%5B2%5D%29%5E2+%29+ = sqrt(9 + 16) = 5