Question 922346: The diagonals of a rhombus are of lengths 10 and 24. What is ots perimeter? Please help. thanks in advance.
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! We use the following steps to find the perimeter given the diagonals,
1) Divide both diagonals in half - we get 5 and 12.
2) Square both halves, then add the squares together. For this problem, 5 squared is 25, and 12 squared is 144; 25 +144 = 169.
3) Calculate the square root of the previous step's sum to find the length of one of the rhombus' sides, and multiply the length by 4 to calculate its perimeter.
Therefore, the square root of 169 is 13, and 13 multiplied by 4 is 52, so the rhombus' perimeter is 52.
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