SOLUTION: Suppose cot t = −0.8 and t is in quadrant IV. Find each of the following sin (t + 4π) = tan (t + 11π) = please give detail on how these are solved. I've f

Algebra ->  Trigonometry-basics -> SOLUTION: Suppose cot t = −0.8 and t is in quadrant IV. Find each of the following sin (t + 4π) = tan (t + 11π) = please give detail on how these are solved. I've f      Log On


   

Question 922090: Suppose cot t = −0.8 and t is in quadrant IV. Find each of the following
sin (t + 4π) =
tan (t + 11π) =
please give detail on how these are solved. I've figured out that opposite = -5, adjacent = 4 and hypotenuse = √41 but I am stuck on solving these.
Thank you
Found 2 solutions by ewatrrr, MathLover1:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
sin (t + 2πn) = sin (t) = -5/√41 = -5√41/41
tan (t + πn )= tan(t) = -5/4

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
cot+%28t%29+=+-0.8=-4%2F5+=+adj%2Fopp
The hypotenuse is sqrt%284%5E2+%2B+5%5E2%29+=+sqrt%2841%29
sin+%28t%29+=+-5%2Fsqrt%2841%29 ...Sine+=+opp%2Fhyp, negative in quadrant IV
cos+%28t%29+=+4%2Fsqrt%2841%29.......%7B%7B%7B+Cosine+=+adj%2Fhyp

sin%28t+%2B+4pi%29+=+sin+%28t%29+=+-5%2Fsqrt%2841%29. The period of sine is 2pi
. The period of tan is pi