SOLUTION: Directions: Solve each problem. A furniture maker has a shop that can employ 12 workers for 40 hour per week at its maximum capacity. The shop makes tables and chairs. It takes

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Directions: Solve each problem. A furniture maker has a shop that can employ 12 workers for 40 hour per week at its maximum capacity. The shop makes tables and chairs. It takes       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 92206: Directions: Solve each problem.
A furniture maker has a shop that can employ 12 workers for 40 hour per week at its maximum capacity. The shop makes tables and chairs. It takes 16 hours of labor to make a table and 8 hours of labor to make a chair. Graph the region that shows the possibilities for the number of tables and chairs that could be made in one week.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A furniture maker has a shop that can employ 12 workers for 40 hour per week at its maximum capacity. The shop makes tables and chairs. It takes 16 hours of labor to make a table and 8 hours of labor to make a chair. Graph the region that shows the possibilities for the number of tables and chairs that could be made in one week.
:
Total man-hours per week: 12*40 = 480 hrs
:
x = no. of tables, y = no. of chairs
:
16x + 8y =< 480
Put in equation into the slope intercept form for graphing
8y =< -16x + 480
y =< -(16/8)x + (480/8)
y =< -2x + 60
:
Graph it from x = 0 to x = 30
:
x | y
-------
0 | 60; all chairs
10 | 40
20 | 20
30 | 0; all tables
:
Your graph should look this:
+graph%28+300%2C+200%2C+-6%2C+36%2C+-6%2C+66%2C+-2x%2B60+%29+
:
The area of feasibility would be at or below the line
:
Did this make sense to you? Any questions?