SOLUTION: log (base 7) 2 + log (base 49) x = log (base 1/7) sqrt 3
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Question 921936
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log (base 7) 2 + log (base 49) x = log (base 1/7) sqrt 3
Answer by
mathsnight(4)
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Log(base7)2sqrt(3)=log(base7)(x^(-1/2)), then
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