SOLUTION: Find the solution set of each of the following over the interval 0 &#8804; x < 2. 1) sin x - 1= 0 2) &#8730;2 cos x + 1= 0 3) tan^2 x - 1= 0

Algebra ->  Trigonometry-basics -> SOLUTION: Find the solution set of each of the following over the interval 0 &#8804; x < 2. 1) sin x - 1= 0 2) &#8730;2 cos x + 1= 0 3) tan^2 x - 1= 0      Log On


   

Question 921858: Find the solution set of each of the following over the interval 0 ≤ x < 2.
1) sin x - 1= 0
2) √2 cos x + 1= 0
3) tan^2 x - 1= 0
Answer by srinivas.g(540) About Me  (Show Source):
You can put this solution on YOUR website!
1)sin x-1 =0
add 1 on both sides
sin x-1+1 =0+1
sinx = 1
+x=sininv%281%29
x =
2) sqrt%282%29cos *x +1=0
subtract 1 on both sides
sqrt%282%29cos *x +1-1 =0-1
sqrt%282%29cos *x =-1
divide with sqrt%282%29 on both sides
1%2Fsqrt%282%29*sqrt%282%29cos *x =-1* 1%2Fsqrt%282%29
cos *x = -1%2Fsqrt%282%29
x = 3π/4
3)
tan^2 x -1 =0
add 1 on both sides
tan^2 x-1+1=0+1
tan^2 x =1
square root on both sides
sqrt(tan^2 x ) = sqrt%281%29
tan x= 1
x = π/4