SOLUTION: Pat is 2 years younger than his wife, Wynn. Ten years ago the sum of their ages was 48 How old are they now? I know I need to assign a variable I believe that would be for wynn

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Question 921808: Pat is 2 years younger than his wife, Wynn. Ten years ago the sum of their ages was 48 How old are they now? I know I need to assign a variable I believe that would be for wynn Pat being 2 yrs younger is throwing me off.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +w+ = wife's age now
+w+-+2+ = Pat's age now
-------------------------
+w+-+10+ = wife's age 10 yrs ago
+w+-+2+-+10+ = Pat's age 10 yrs ago
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+w+-+10+%2B+w+-+2+-+10+=+48+
+2w+-+22+=+48+
+2w+=+70+
+w+=+35+
+w+-+2+=+33+
---------------
Pat is 33
Pat's wife is 35
--------------
check:
10 yrs ago,
Pat was 23
Pat's wife was 25
----------------
+23+%2B+25+=+48+
+48+=+48+
OK