Question 921801: in an isosceles triangle abc, if ab= bc,. If ab= 5x+ 10, BC 3x+40, and Ac= 2x+30, find the length of each side
Found 2 solutions by starrlitee, MathTherapy:
Answer by starrlitee(1)   (Show Source):
You can put this solution on YOUR website! Add all three sides and set equal to 180.
(5x+10)+(3x+40)+(2x+30)=180
Add like terms.
10x+80=180
Subtract 80 from each side
10x=100
Divide by ten to solve for x.
X=10
Put x into each individual side.
5x+10~ 5(10)+10 = ab=60
3x+40~ 3(10)+40 = bc= 70
2x+30~ 2(10)+30 = ac= 50
To check your work, add all three sides they should add up to 180.
70+60+50=180
:)
Answer by MathTherapy(10549)  (Show Source):
You can put this solution on YOUR website!
in an isosceles triangle abc, if ab= bc,. If ab= 5x+ 10, BC 3x+40, and Ac= 2x+30, find the length of each side
Since AB = BC, then: 5x + 10 = 3x + 40
5x - 3x = 40 - 10
2x = 30
x =  , or 15 units
Side AB: 5(15) + 10, or 75 + 10, or  units
Side BC is also: units
Side AC: 2(15) + 30, or 30 + 30, or  units
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