Question 921720: find four consecutive odd integers such that the sum of the two largest integers subtracted from twice the sum of two smallest integers is 96
Answer by CubeyThePenguin(3113) (Show Source):
You can put this solution on YOUR website! 4 consecutive odd integers: x, (x+2), (x+4), (x+6)
2(x + (x+2)) - ((x+4) + (x+6)) = 96
2(2x + 2) - (2x + 10) = 96
4x + 4 - 2x - 10 = 96
2x = 102
x = 51
The integers are 51, 53, 55, and 57.
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