Question 921720:  find four consecutive odd integers such that the sum of the two largest integers subtracted from twice the sum of two smallest integers is 96 
 Answer by CubeyThePenguin(3113)      (Show Source): 
You can  put this solution on YOUR website! 4 consecutive odd integers: x, (x+2), (x+4), (x+6)
 
 
2(x + (x+2)) - ((x+4) + (x+6)) = 96 
2(2x + 2) - (2x + 10) = 96 
4x + 4 - 2x - 10 = 96 
2x = 102 
x = 51
 
 
The integers are 51, 53, 55, and 57. 
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