SOLUTION: Three machines A,B,C operating at the same time can do a job in 8 hours. If A alone operates for 2 hours and B alone for 3 hours, one-fourth of the job is done. Now if B alone ope

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Three machines A,B,C operating at the same time can do a job in 8 hours. If A alone operates for 2 hours and B alone for 3 hours, one-fourth of the job is done. Now if B alone ope      Log On


   



Question 921634: Three machines A,B,C operating at the same time can do a job in 8 hours. If A alone operates for 2 hours and B alone for 3 hours, one-fourth of the job is done. Now if B alone operates for 5 hours and C alone for 14 hours, one-half of the job is done. How many hours would it take each to do the job alone?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Three machines A,B,C operating at the same time can do a job in 8 hours.
If A alone operates for 2 hours and B alone for 3 hours, one-fourth of the job is done.
Now if B alone operates for 5 hours and C alone for 14 hours, one-half of the job is done.
How many hours would it take each to do the job alone?
:
let a = time required by machine A alone
let b = time required by B
let c = time required by C
:
Write an equation for each statement.
:
let the completed job = 1
:
Three machines A,B,C operating at the same time can do a job in 8 hours.
8%2Fa + 8%2Fb + 8%2Fc = 1
:
If A alone operates for 2 hours and B alone for 3 hours, one-fourth of the job is done.
2%2Fa + 3%2Fb = 1%2F4
:
Now if B alone operates for 5 hours and C alone for 14 hours, one-half of the job is done.
5%2Fb + 14%2Fc = 1%2F2
:
multiply the 2nd equation by 4, subtract from the 1st equation
8%2Fa + 8%2Fb + 8%2Fc = 1
8%2Fa + 12%2Fb + 0 = 1
---------------------------------subtraction eliminates a
0 - 4%2Fb + 8%2Fc = 0
8%2Fc = 4%2Fb
divide both sides 4
2%2Fc = 1%2Fb
cross multiply
1c = 2b
in the 3rd original equation replace c with 2b
5%2Fb + 14%2F%282b%29 = 1%2F2
Reduce the fraction
5%2Fb + 7%2Fb = 1%2F2
12%2Fb = 1%2F2
b = 24 hrs working alone
then
c = 2(24)
c = 48 hrs alone
In the 2nd original equation, replace b with 24
2%2Fa + 3%2F24 = 1%2F4
reduce fraction
2%2Fa + 1%2F8 = 1%2F4
2%2Fa = 1%2F4 - 1%2F8
2%2Fa = 1%2F8
a = 16 hrs working alone
:
:
You can confirm this yourself using the 1st equation
8%2F16 + 8%2F24 + 8%2F48 = 1