SOLUTION: (8/3)^4*8^3 (4a^2b^3)^-2(2ab^-1)^3 the last one how can i make (10^2)^3 to 1000^6

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: (8/3)^4*8^3 (4a^2b^3)^-2(2ab^-1)^3 the last one how can i make (10^2)^3 to 1000^6      Log On


   

Question 9216: (8/3)^4*8^3
(4a^2b^3)^-2(2ab^-1)^3
the last one how can i make (10^2)^3 to 1000^6
Answer by rahman(247) About Me  (Show Source):
You can put this solution on YOUR website!
1. %288%2F3%29%5E4%2A8%5E3+=+%288%5E4%2A8%5E3%29%2F3%5E4=8%5E%284%2B3%29%2F3%5E4=8%5E7%2F3%5E4
Remember:
a^-n=1/a^n; when a is real except zero
2. %284a%5E2b%5E3%29%5E-2%282ab%5E-1%29%5E3=%281%2F%28%284a%5E2b%5E3%29%5E2%29%29%2A%282ab%5E-1%29%5E3=%282ab%5E-1%29%5E3%2F%284a%5E2b%5E3%29%5E2=2%5E3%2Aa%5E3%2Ab%5E-3%2F%284%5E2%2Aa%5E4%2Ab%5E6%29=2%5E3%2F%284%5E2%2Aa%5E%284-3%29%2Ab%5E%286-%28-3%29%29%29=8%2F%2816%2Aa%2Ab%5E9%29=1%2F2ab%5E9
3. %2810%5E2%29%5E3=10%5E2%2A10%5E2%2A10%5E2=10%5E%282%2B2%2B2%29=10%5E6
Ok