SOLUTION: The Vertex of This Parabola is at (3,5). When the y-value is 6, the x-value is -1 what is the coefficient of the squared term in the parabola's equation?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: The Vertex of This Parabola is at (3,5). When the y-value is 6, the x-value is -1 what is the coefficient of the squared term in the parabola's equation?       Log On


   

Question 921569: The Vertex of This Parabola is at (3,5). When the y-value is 6, the x-value is -1 what is the coefficient of the squared term in the parabola's equation?
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
The Vertex of This Parabola is at (3,5). When the y-value is 6, the x-value is
-1 what is the coefficient of the squared term in the parabola's equation?
y+=+a%28x-h%29%5E2%2Bk

The Vertex of This Parabola is at (3,5)

So (h,k) = (3,5)

y+=+a%28x-3%29%5E2%2B5

When the y-value is 6, the x-value is -1

6+=+a%28-1-3%29%5E2%2B5
6+=+a%28-4%29%5E2%2B5
6+=+a%2816%29%2B5
6+=+16a%2B5
1+=+16a
1%2F16+=+a  <-- that's the answer as we shall see:

y+=+expr%281%2F16%29%28x-3%29%5E2%2B5
y+=+expr%281%2F16%29%28x%5E2-6x%2B9%29%2B5
y+=+expr%281%2F16%29x%5E2-expr%283%2F8%29x%2B9%2F16%2B5
y+=+expr%281%2F16%29x%5E2-expr%283%2F8%29x%2B9%2F16%2B80%2F16
y+=+expr%281%2F16%29x%5E2-expr%283%2F8%29x%2B89%2F16

So the coefficient of the squared term is 1%2F16.

Edwin