Question 921370: In a survey of 1000 eligible voters selected at random, it was found that 200 had a college degree. Additionally, it was found that 90% of those who had a college degree voted in the last presidential election, whereas 60% of the people who did not have a college degree voted in the last presidential election. Assuming that the poll is representative of all eligible voters, find the probability that an eligible voter selected at random will have the following characteristics. (Round your answers to three decimal places.)
(a) The voter had a college degree and voted in the last presidential election.
(b) The voter did not have a college degree and did not vote in the last presidential election.
(c) The voter voted in the last presidential election.
(d) The voter did not vote in the last presidential election.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In a survey of 1000 eligible voters selected at random, it was found that 200 had a college degree. Additionally, it was found that 90% of those who had a college degree voted in the last presidential election, whereas 60% of the people who did not have a college degree voted in the last presidential election. Assuming that the poll is representative of all eligible voters, find the probability that an eligible voter selected at random will have the following characteristics. (Round your answers to three decimal places.)
------
Draw a contingincy table with rows = degree/no degree
and columns vote/not vote
-------------------
.................vote..no vot
Degree looks like 180...20...200
no Deg looks like 480..320...800
totals looks like 660..340...1000
------------------------------------------
(a) The voter had a college degree and voted in the last presidential election.
P = 180/1000 = 18%
--------------------------------
(b) The voter did not have a college degree and did not vote in the last presidential election.
P = 320/1000 = 32%
---------------------------
(c) The voter voted in the last presidential election.
P = 660/1000 = 66%
---------------------------
(d) The voter did not vote in the last presidential election.
P = 340/1000 = 34%
===================
Cheers,
Stan H.
===================
|
|
|
