SOLUTION: Working on the following problem for 7th grade Algebra: Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: Working on the following problem for 7th grade Algebra: Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of      Log On


   

Question 921315: Working on the following problem for 7th grade Algebra:
Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. Here is the problem listed: (1, -3);y+2=4(x-1)

Totally lost on where to begin.
Thanks!
Found 2 solutions by josmiceli, MathLover1:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Parallel means it has the same slope
+y+%2B+2+=+4%2A%28+x-1+%29+
+y+=+4x+-+4+-+2+
+y+=+4x+-+6+
slope = +4+
-----------------
(1,-3)
Use the general point-slope equation:
+%28+y+-+%28-3%29+%29+%2F+%28+x+-+1+%29+=+4+
+%28+y+%2B+3+%29+%2F+%28+x+-+1+%29+=+4+
+y+%2B+3+=+4%2A%28+x+-+1+%29+
+y+=+4x+-+4+-+3+
+y+=+4x+-+7+
-------------
Does it go through ( 1,-3 )?
+-3+=+4%2A1+-+7+
+-3+=+-3+
OK
Is it parallel to
+y+=+4x+-+6+?
Same slope -yes

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
an equation in slope-intercept form is: y=mx%2Bb where m is a slope and b is y-intercept
given:
point (1, -3)
y%2B2=4%28x-1%29
to find: an equation of a line that passes through the given point and is parallel to the graph of the given equation

first write y%2B2=4%28x-1%29 in slope-intercept form; we need to know what a slope is
y=4%28x-1%29-2
y=4x-4-2
y=highlight%284%29x-6...as you can see, the slope m%5B1%5D=4
you also know that parallel lines have same+slope; so, the line parallel to given line has slope m%5B2%5D=4
now, plug it in slope-intercept form:
y=highlight%284%29x%2Bb , now use given point (1, -3) and substitute 1 for x and -3 for y

-3=4%2A1%2Bb .........solve for b
-3=4%2A1%2Bb
-3=4%2Bb
-3-4=b
-7=b
go back to y=highlight%284%29x%2Bb, plug in b
highlight%28y=4x-7%29 ....this is an equation of a line parallel to y%2B2=4%28x-1%29 and passes through the point (1, -3)
here is the graph: