SOLUTION: Find the exact value of the trigonometric function given that sin u =20/29 and cos v = −8/17 . (Both u and v are in Quadrant II.) csc(u − v)

Algebra ->  Trigonometry-basics -> SOLUTION: Find the exact value of the trigonometric function given that sin u =20/29 and cos v = −8/17 . (Both u and v are in Quadrant II.) csc(u − v)      Log On


   



Question 921232: Find the exact value of the trigonometric function given that
sin u =20/29
and
cos v = −8/17
.
(Both u and v are in Quadrant II.)
csc(u − v)

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
sin u = 20/29, cos u = -21/29 sqrt%2829%5E2+-+20%5E2+%29=+21
cos v = -8/17, sin v = 15/17 sqrt%2817%5E2+-+8%5E2+%29=+15
.......
csc(u - v) = 1 / sin(u - v) = 1/(sin u cos v - cos u sin v)
Let you finish it Up