SOLUTION: {{{ 2 [f(x^2)-5]}}} if {{{f(x)=3x+7}}} The first two is supposed to be multiplying not an exponent. I don't know why it is doing that. Thank you so much!

Algebra ->  Functions -> SOLUTION: {{{ 2 [f(x^2)-5]}}} if {{{f(x)=3x+7}}} The first two is supposed to be multiplying not an exponent. I don't know why it is doing that. Thank you so much!      Log On


   

Question 920991: +2+%5Bf%28x%5E2%29-5%5D
if f%28x%29=3x%2B7
The first two is supposed to be multiplying not an exponent. I don't know why it is doing that.
Thank you so much!
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
The square brackets surrounding a character or expression makes rendering as a subscript on this site.

2*f(x^2)-5 in pure text, is what you want to evaluate or simplify;
2f%28x%5E2%29-5 when the rendering tags are added.

Nothing more to do for what you are showing. x itself is not given. Maybe you want to replace x with x^2?

f%28x%5E2%29=3%28x%5E2%29%2B7
f%28x%5E2%29=3x%5E2%2B7
Now, you want to find 2%28f%28x%5E2%29%29-5
2%283x%5E2%2B7%29-5
6x%5E2%2B14-5
highlight%286x%5E2%2B9%29