Question 920768: A car travels from P to Q at a constant speed. If its speed were increased by 10 km/h, it would have been taken one hour lesser to cover the distance. It would have taken further 45 minutes lesser if the speed was further increased by 10 km/h. the distance between the two cities is
please solved this question starting to ending.
Answer by multiplier(8)   (Show Source):
You can put this solution on YOUR website! let v- constant speed of car in km/hr
s- distance between the two cities(P to Q) in kilometers
t- time to travel from P to Q in hours
working formula: s=vt
cond. 1: s=vt >(Eq 1)
cond. 2: v is increase by 10 km/hr, the value of (v) in (Eq 1) becomes
(v+10), and (t) in will be (t-1)
s=(v+10)(t-1) > (Eq 2)
cond. 3:v is increased further by 10km/hr, time is cut by 45 minutes
s=(v+20)(t-7/4) >(Eq 3)... (7/4= 1 hr and 45 minutes)
since distance from P & Q is constant, s will be same in all conditions
equate (Eq 1), (Eq 2) and (Eq 3)
v=60km/hr; t=7 hours
s=420 km-the distance you are looking for...
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