SOLUTION: Find the exact value:
i. tan (5π/3) sec (-5π/6) =
ii. sin (27π/4) cos (1043 π)
Please explain
Thank you
Algebra ->
Trigonometry-basics
-> SOLUTION: Find the exact value:
i. tan (5π/3) sec (-5π/6) =
ii. sin (27π/4) cos (1043 π)
Please explain
Thank you
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You can put this solution on YOUR website! Find the exact value:
i. tan (5π/3) sec (-5π/6) =
tan(5π/3)=tan(π/3) in quadrant IV=-√3
sec(-5π/6)=1/cos(-5π/6)=1/cos(π/6)(in quadrant III)=1/-(√3/2)=-2/√3
tan (5π/3) sec (-5π/6) =-√3*-2/√3=2
..
ii. sin (27π/4) cos (1043 π)
sin (27π/4)=sin(3π/4)=sin(π/4)(in quadrant II)=√2/2
cos (1043 π)=cos(1042π+π)=cosπ=-1
sin (27π/4) cos (1043 π)=-1*√2/2=-√2/2
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