SOLUTION: how to graph: x^2+4y^2+4x-8y-8

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Question 920593: how to graph: x^2+4y^2+4x-8y-8
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+4y^2+4x-8y-8 = 0
(x-2)^2-4 + 4(y-1)^2 -4 -8 = 0
(x-2)^2 + 4(y-1)^2 = 16
(x-2)^2/16 + (y-1)^2/4 = 1 Ellipse C(2,1) major axis along y = 1
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
%28x-2%29%5E2%2F4%5E2+%2B+%28y-2%29%5E2%2F2%5E2+=+1+