SOLUTION: Suppose sin u = - 2/9 and tan u < 0. a. Locate the terminal point Pu for u on the unit circle and find its coordinates. b. Find the exact value of each of the following: i.

Algebra ->  Trigonometry-basics -> SOLUTION: Suppose sin u = - 2/9 and tan u < 0. a. Locate the terminal point Pu for u on the unit circle and find its coordinates. b. Find the exact value of each of the following: i.       Log On


   

Question 920583: Suppose sin u = - 2/9 and tan u < 0.
a. Locate the terminal point Pu for u on the unit circle and find its coordinates.
b. Find the exact value of each of the following:
i. cos (74π – u)
ii. tan (u + 3π/2)
iii. csc (-u )
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose sin u = - 2/9 and tan u < 0.
given data shows reference angle u is in quadrant IV where sin<0, cos>0
cos u=√(1-sin^2 u)=√(1-4/81)/√(77/81)=√77/9
..
a. Locate the terminal point Pu for u on the unit circle and find its coordinates.
P(u)=(-2/9,√77/9)
..
b. Find the exact value of each of the following:
i. cos (74π – u)=cos u
..
ii. tan (u + 3π/2)=2π-u=-tan u
..
iii. csc (-u )=1/sin (-u)=1/-sin u=-csc u