SOLUTION: Understanding sinusoidal graphing. With amp, period, shift?
For the problem: g(x) = -2sin(πx + π/3)
From the form: Y = Asin(bx+c)+d
I understand that the amplitude i
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-> SOLUTION: Understanding sinusoidal graphing. With amp, period, shift?
For the problem: g(x) = -2sin(πx + π/3)
From the form: Y = Asin(bx+c)+d
I understand that the amplitude i
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Question 920541: Understanding sinusoidal graphing. With amp, period, shift?
For the problem: g(x) = -2sin(πx + π/3)
From the form: Y = Asin(bx+c)+d
I understand that the amplitude is |A| and therefore amplitude = 2
Also, I know the period is 2π/|b| and therefore the period = 2
The phase shift is C/B and therefore π/3/π or bx+c = 0 πx + π/3 = 0 πx=-π/3 x= -π/3/π x=-1/3
I understand how to find those fine but it's the actual graphing of it that I am having trouble understanding. How would I aggregate this information to created a graph? I know that cos(0) = 1 and therefore starts from the top and descends and sin(0) = 0 so it starts from the origin and ascends then descends.
I know that the horizontal asymptotes are both at the amplitudes.
My main question is how is the phase shift and period applied to the overall graph? what are they doing to the curve and the rest of the graph? and have would I apply that to this graph Please help Thank you Answer by rothauserc(4718) (Show Source):
