SOLUTION: how do you solve log(n+2)+log 8=log(n^2+7n+10

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Question 920446: how do you solve log(n+2)+log 8=log(n^2+7n+10
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log(n+2)+log 8=log(n^2+7n+10
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log[(n+2)(8)] = log(n^2+7n+10)
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8n+16 = n^2+7n+10
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n^2 - n - 6 = 0
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Factor::
(n-3)(n+2) = 0
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n = 3
or
n = -2 (extraneous)
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Cheers,
Stan H.
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