SOLUTION: Find the amplitude, Period, Phase Shift, Graph and max/min and x and y intercepts of: g(t) = -2sin(πt + π/3) Please give a detailed answer for this. I think I under

Algebra ->  Trigonometry-basics -> SOLUTION: Find the amplitude, Period, Phase Shift, Graph and max/min and x and y intercepts of: g(t) = -2sin(πt + π/3) Please give a detailed answer for this. I think I under      Log On


   



Question 920439: Find the amplitude, Period, Phase Shift, Graph and max/min and x and y intercepts of:
g(t) = -2sin(πt + π/3)
Please give a detailed answer for this. I think I understand the amplitude being the height from the negative or positive of the y axis. And therefore it would be from 2 to -2? And it's always the absolute of the first number.
The period I think is the number of times It goes around and I think that is the π/3 part
The phase shift not sure
and how to find the max and min, not sure
or the x and y intercepts.
Please help
Thank you

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
the general formula is:

y = a*(sin(b(x-c))+d

|a| is the amplitude
b is the frequency
c is the horizontal shift
d is the vertical shift.

replace t with x and your equation is:

y = -2 * sin( pi * x + pi/3)

this can also be written as:

y = -2 * sin( pi * (x + 1/3))

the general equation is, once again:

y = a * (sin( b * (x-c)) + d

in your equation:

|a| = 2
b = pi
c = 1/3
d = 0

your amplitude is equal to 2
your frequency is equal to pi
your horizontal shift is equal to -1/3
your vertical shift is equal to 0

your period is equal to 2*pi divided by your frequency.
this makes your period equal to 2*pi / pi = 2

everything is in radians.

your equation looks like this:

picture 1

the period is equal to 2 and goes from -1/3 to 5/3.
your amplitude is equal to 2 so the graph goes from a high of 2 to a low of -2.
there is no vertical shift because d = 0.

take away the horizontal shift and your graph looks like this:

picture 2

everything else remains the same except there is no more horizontal shift so the period goes from 0 to 2.

your y intercept is the value of y when x = 0.

your equation is, once again:

y = -2 * sin( pi * (x + 1/3))

when x = 0, y = -2 * sin(pi/3)

pi/3 = 60 degrees and sin (60) = sqrt(3)/2

-2*sqrt(3)/2) = -sqrt(3) which is equivalent to -1.73.....

you can see that on the following graph.

that's the value of y when x = 0

picture 3

the x-intercept is the value of x when y = 0

set your equation and solve for x.

you get:

0 = -2sin(pi(x+1/3))

divide both sides by -2 and you get:

sin(pi(x+1/3) = 0

this is true if and only if arc-sine(0) = pi(x+1/3)

arc-sin(0) = 0 so pi(x+1/3) = 0 which results in x = -1/3.

the value of y is 0 when x = -1/3.

picture 4

here's a good reference on the general formula used.

http://www.regentsprep.org/regents/math/algtrig/ATT7/sinusoidal.htm