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Question 920410: let f(x) = 12x^2 - 29x+10, and let a=10. find f(a+h) - f(a)/h
f(x)=-5/23 x+33, and a=-12, find f(x)-f(a)/x-a
f(x)=-x^2 +2x+15, and g(x)=18x^3 -11x^2-24x-21, find (f-g)(-2)
f(x)=-9x^2+10x+4, and g(x)=-7x^3-24x+6, find (f-g)(8)
f(x)=10x^2+11x+8, and g(x)=11x^3+4x^2-8x+3, find(f/g)(1)
f(x)=16x^2+19x+1, and g(x)=20x+21, find f/g (y)
f(x)=9x^2-11x-7, find f(x+h)-f(x)/h
im am stuck, any help would be appreciated
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! let f(x) = 12x^2 - 29x+10, and let a=10. find f(a+h) - f(a)/h
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Find f(a+h). Wherever there's an x, sub (a+h)
f(a+h) = 12(a+h)^2 - 29(a+h) + 10 ***** That's all it is, just substitution.
Then simplify some.
f(a+h) = 12a^2 + 24ah + 12h^2 - 29a - 29h + 10
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then find f(a). Sub a for x
f(a) = 12a^2 - 29a + 10
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f(a+h) = 12a^2 + 24ah + 12h^2 - 29a - 29h + 10
f(a) = 12a^2 - 29a + 10
------------------------------------- Subtract
f(a+h)-f(a) = 24ah + 12h^2 - 29h
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Divide by h
[f(a+h)-f(a)]/h = 24a + 12h - 29
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f(x)=-5/23 x+33, and a=-12, find f(x)-f(a)/x-a
Similar to the 1st one. Try it.
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f(x)=-x^2 +2x+15, and g(x)=18x^3 -11x^2-24x-21, find (f-g)(-2)
That means f(-2) - g(-2). Sub -2, then subtract.
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f(x)=-9x^2+10x+4, and g(x)=-7x^3-24x+6, find (f-g)(8)
Same as above.
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f(x)=10x^2+11x+8, and g(x)=11x^3+4x^2-8x+3, find(f/g)(1)
--> f(1)/g(1)
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f(x)=16x^2+19x+1, and g(x)=20x+21, find f/g (y)
--> f(y)/g(y)
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f(x)=9x^2-11x-7, find f(x+h)-f(x)/h
Same as #1
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