SOLUTION: If 2^x = 15 and 15^y = 32, find xy

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Question 920385: If 2^x = 15 and 15^y = 32, find xy
Answer by mathsnight(4) About Me  (Show Source):
You can put this solution on YOUR website!
Using log properties:
xlog2=log15
and
ylog15=log32, which is
log15=log32%2Fy , then,
xlog2=log32%2Fy , now divide both sides by ' log2 ' and cross multiply 'y' with 'x'
=> xy=log32%2Flog2 , finally,
xy=5