SOLUTION: The sum of 4 consectutive odd integers is ten less than the square of the first odd integer

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Question 920273: The sum of 4 consectutive odd integers is ten less than the square of the first odd integer
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: x, (x+2), (x+4), (x+6)

x + (x+2) + (x+4) + (x+6) = x^2 - 10
4x + 12 = x^2 - 10
0 = x^2 - 4x - 22

This equation has no integer solutions.