SOLUTION: What is the equation of the line that passes through (-4,-1) that is PERPENDICULAR to the line that passes through the points (-2,-1) and (0,4) ?

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Question 920228: What is the equation of the line that passes through (-4,-1) that is PERPENDICULAR to the line that passes through the points (-2,-1) and (0,4) ?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
(-2,-1) and
(0,4) m =%28y%5B1%5D+-+y%5B2%5D%29%2F%28x%5B1%5D+-+x%5B2%5D+%29 = -5/-2 = 5/2
....
Line PERPENDICULAR to this has m = -2/5
***Using point-slope form, y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29 P(-1,-1)
y + 1 = (-2/5)(x+1)
y = (-2/5)x - 7/5
0r...In standard Form
2x + 5y = -7