SOLUTION: Use inverse functions where needed to find all solutions of the equation in the interval [0, 2π). (Enter your answers as a comma-separated list.) 2 sin^2 x + 9 cos x = 6

Algebra ->  Trigonometry-basics -> SOLUTION: Use inverse functions where needed to find all solutions of the equation in the interval [0, 2π). (Enter your answers as a comma-separated list.) 2 sin^2 x + 9 cos x = 6       Log On


   



Question 920116: Use inverse functions where needed to find all solutions of the equation in the interval [0, 2π). (Enter your answers as a comma-separated list.)
2 sin^2 x + 9 cos x = 6

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
2(1-cos^2 x) + 9cos x = 6
2 - 2cos^2 x + 9cosx = 6
2cos^2 x - 9cosx + 4 = 0
(2cosx -1)(cosx - 4) = 0 (cosx = 4 Invalid)
cosx = 1/2
x = π/3, 5π/3
(cosx, sinsx) Summary Unit Circle for You Referecne
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