SOLUTION: Find 2 consecutive positive integers such that the square of the first number is 1 more than 9 times the second number

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Question 919920: Find 2 consecutive positive integers such that the square of the first number is 1 more than 9 times the second number
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive positive integers: x, (x+1)

x^2 = 1 + 9(x+1)
x^2 = 1 + 9x + 9
x^2 - 9x - 10 = 0
(x - 10)(x + 1) = 0

The integers are positive, so x = 10 and the integers are 10 and 11.